Avarage Posts Per Day

[Andrew]

I was thinking that we should have it. It shows whos been posting alot.

<script>
//Average Posts/Day only displayed in Profile v2.0

//Copyright 10-15-2005 ~Wonder
//May be reposted anywhere as long as this header remains in tact

//Put In Global Header

function getDate(d,fs)
{
ty="";
if(ty=d.match(/(To|Yester)day/i)){d=document.getElementsByTagName("table")[0].innerHTML.match(/\.<br>.+ \d{1,2}\:/i)[0].replace(/\d{1,2}:/,"")+d.match(/( \d{1,2}\:\d{2}(a|pm)?)/);}
months=new Array("jan","feb","mar","apr","may","jun","jul","aug","sep","oct","nov","dec");te=0;
curDate=d.match(/.+ (\d{1,2}\:\d{2}(a|pm)?)/i)[0];
time=RegExp.$1;dm=0;
curDate=curDate.toLowerCase().replace(/\.<br>/i,"").replace(time,"").replace(/ at /i,"").replace(/,/g,"").replace(/\.|\-|\//g," ").split(" ");
time=time.split(":");
if(time[1].match(/am/) && time[0].match(/12/)){time[0]=parseInt(time[0],10)-12;}
if(time[1].match(/pm/) && !time[0].match(/12/)){time[0]=parseInt(time[0],10)+12;}time[1]=time[1].replace(/[^\d]/g,"");
for(k=0;k<12;k++){if(curDate[0].match(months[k]) || curDate[1].match(months[k])){break;}}
if((t=curDate[0].match(months[k]))!=null && t!=""){curDate[0]=(k+1)+"";te=1;fs=0;}else if((t=curDate[1].match(months[k]))!=null && t!=""){curDate[1]=(k+1)+"";fs=1;temp2=curDate[1];curDate[1]=curDate[0];curDate[0]=temp2;te=1;}
curDate[0]=curDate[0].replace(/[^\d]/g,"");curDate[1]=curDate[1].replace(/[^\d]/g,"");
if(parseInt(curDate[0],10)>12){fs=1;te=1;temp2=curDate[1];curDate[1]=curDate[0];curDate[0]=temp2;}
if(parseInt(curDate[1],10)<13 && te==0)
{
if(fs==1){temp2=curDate[1];curDate[1]=curDate[0];curDate[0]=temp2;}
else if(fs==0){}
else
{
now = new Date();fs=0;
if(parseInt(curDate[1],10)==(now.getMonth()+1))
{
temp2=curDate[1];
curDate[1]=curDate[0];
curDate[0]=temp2;fs=1;
}
}
}
if(curDate[2].length<=2){curDate[2]=parseInt(curDate[2],10)+2000;}if(ty!=null && ty[0].match(/yesterday/i)){dm=1;}
return [new Date(parseInt(curDate[2],10),parseInt(curDate[0],10)-1,parseInt(curDate[1],10)-dm,parseInt(time[0],10),parseInt(time[1],10)),fs];
}
mainDate=getDate(document.getElementsByTagName("table")[0].innerHTML.match(/\.<br>.+ (\d{1,2}\:\d{2}(a|pm)?)/i)[0]);
</script>

[Shanks5974]

We did used to have this but it was removed to help speed up the forums loading times (those who have been around for a couple of years or more will know the forum used to be a lot slower loading)

[Andrew]

Oh ok, thats fine